Calculate the expected final temperature for 1.02 kg of a substance which absorbs 1.50 kJ of heat energy, if it starts at 12.1°C and has a specific heat capacity of 149 Jkg-1°C-1
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Q = mcΔT
ΔT = Q ÷ (mc) = 1500 ÷ (1.02 × 149) = 9.87 °C
Absorbs energy so temperature increases. Final temperature is 12.1 + 9.87 = 22.0°C
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